# What is the standard form of y= 2(7/5x + 14)^2 - 1 ?

Oct 24, 2017

The expression can be standardized as:
 y = 98/25x² + 392/5x + 391

#### Explanation:

To put the expression in the standard form, apply the power on the parentheses:

y = 2 * (7/5 x + 14)^² - 1
y = 2 * (49/25x²+ 2 * (7/5x) * 14 + 196) - 1
y = 2 * (49/25x²+ 196/5x + 196) -1

Now, multiply the inside of the parentheses by 2 (the number outside multiplying it):

y = 98/25x² + 392/5x + 392 - 1 = 98/25x² + 392/5x + 391