What is the standard form of $y=(2x-1)(3x+4)$ ?

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Answer 1 · 2016-01-13T23:03:38

$y=6x^2+5x-4$

Distribute this using the FOIL method.

$y=(2x-1)(3x+4)=overbrace(2x*3x)^"First"+overbrace(2x*4)^"Outside"+overbrace(-1*3x)^"Inside"+overbrace(-1*4)^"Last"$

$=6x^2+8x-3x-4$

Combine like terms.

$=6x^2+5x-4$

This is in standard form since the exponents are in descending order.

What is the standard form of y=(2x-1)(3x+4) y=(2x-1)(3x+4) ?