What is the standard form of $y= (-2x-1/5)(3/7x-1)$ ?

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Answer 1 · 2015-11-19T03:35:48

Find standard form

$y = -(2x + 1/5)((3x)/7 - 1)$ = -35(10x + 1)(3x - 7) #

$y = -35(30x^2 - 70x + 3x - 7) = -35(30x^2 - 67x - 7)$

What is the standard form of y= (-2x-1/5)(3/7x-1) y= (-2x-1/5)(3/7x-1) ?