# What is the standard form of y= (-2x^2-2)(4x-1) ?

$- 8 {x}^{3} + 2 {x}^{2} - 8 x + 2$
$- 2 {x}^{2} \left(4 x - 1\right) - 2 \left(4 x - 1\right) = - 8 {x}^{3} + 2 {x}^{2} - 8 x + 2$
$= - 8 {x}^{3} + 2 {x}^{2} - 8 x + 2$