# What is the standard form of  y= (2x-2)(2x+2)(-x+8)?

Feb 15, 2016

$y$ = $- 4 {x}^{3} + 32 {x}^{2} + 4 x - 32$

#### Explanation:

Standard form of equation y=(2x−2)(2x+2)(−x+8) can be got by multiplying them and combining like terms.

y=(2x−2)(2x+2)(−x+8)

= $\left({\left(2 x\right)}^{2} - {2}^{2}\right) \left(- x + 8\right)$

= $\left(4 {x}^{2} - 4\right) \left(- x + 8\right)$ ie

$y$ = $- 4 {x}^{3} + 32 {x}^{2} + 4 x - 32$