# What is the standard form of y= 2x(4x-2)(x-4)-x+2?

Apr 11, 2018

#### Explanation:

First step is two expand the brackets:

$y = 2 x \left(4 x - 2\right) \left(x - 4\right) - x + 2$

$y = \left(8 {x}^{2} - 4 x\right) \left(x - 4\right) - x + 2$

$y = \left(8 {x}^{3} - 32 {x}^{2} - 16 {x}^{2} + 16 x\right) - x + 2$

Then simplify:

$y = 8 {x}^{3} - 48 {x}^{2} + 15 x + 2$