# What is the standard form of y=(2x-7)(-x+2) -5x^2-8?

Dec 25, 2015

$y = - 7 {x}^{2} + 11 x - 22$

#### Explanation:

To write this in standard form, we need to

1) Multiply/Expand the fist two factor

2) Then combine like terms

$y = \left(2 x - 7\right) \left(- x + 2\right) - 5 {x}^{2} - 8$

$\implies \left(- 2 {x}^{2} + 4 x + 7 x - 14\right) - 5 {x}^{2} - 8$
$\implies - 2 {x}^{2} + 11 x - 14 - 5 {x}^{2} - 8$
$\implies y = - 7 {x}^{2} + 11 x - 22$