What is the standard form of y=(2x−7)(−x+2)−5x2−8?

1 Answer
Vikki
Dec 25, 2015

y=−7x2+11x−22

Explanation:

To write this in standard form, we need to

1) Multiply/Expand the fist two factor

2) Then combine like terms

y=(2x−7)(−x+2)−5x2−8

⇒(−2x2+4x+7x−14)−5x2−8
⇒−2x2+11x−14−5x2−8
⇒y=−7x2+11x−22

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