# What is the standard form of y=(3x - 15)(x - 5) ?

Mar 8, 2016

Standard form is $y = 3 {x}^{2} - 30 x + 75$

#### Explanation:

Standard form of quadratic polynomial with one variable is $y = a {x}^{2} + b x + c$ Hence to convert y=(3x−15)(x−5), one should expand the RHS.

y=(3x−15)(x−5)=3x(x-5)-15(x-5)

= $3 {x}^{2} - 15 x - 15 x + 75$ or

= $3 {x}^{2} - 30 x + 75$