# What is the standard form of y=(3x-5)(2x+11)?

Dec 12, 2015

$y = 6 {x}^{2} + 23 x - 55$

#### Explanation:

Standard form is $y = a {x}^{2} + b x + c$

So you want to multiply the two factors together.
You can use Foil where you multiply the first two terms then the outer, inner, and last terms. Then add them together

$3 x \cdot 2 x = 6 x$

$3 x \cdot 11 = 33 x$

$- 5 \cdot 2 x = - 10 x$

$- 5 \cdot 11 = - 55$

$y = 6 {x}^{2} + 33 x + \left(- 10 x\right) + \left(- 55\right)$

Combine like terms

$y = 6 {x}^{2} + 23 x - 55$