What is the standard form of $y = (3 x - 5) (2 x + 3) (x + 5)$ $y= (3x-5)(2x+3)(x+5)$ ?

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Answer 1 · 2018-05-16T12:19:36

$6 x^{3} + 29 x^{2} - 20 x - 75 - y = 0$ $6x^{3}+29x^{2}-20x-75-y=0$

expand the brackets.

Expanding the first two brackets give you:
$y = (6 x^{2} - x - 15) (x + 5)$ $y=(6x^{2}-x-15)(x+5)$

Expand the rest of it gives you:
$y = 6 x^{3} + 29 x^{2} - 20 x - 75$ $y=6x^{3}+29x^{2}-20x-75$

take the y to the other side to give the given answer.

What is the standard form of y=(3x−5)(2x+3)(x+5) y= (3x-5)(2x+3)(x+5)?