# What is the standard form of  y= (3x-5)(2x+3)(x+5)?

May 16, 2018

$6 {x}^{3} + 29 {x}^{2} - 20 x - 75 - y = 0$

#### Explanation:

expand the brackets.

Expanding the first two brackets give you:
$y = \left(6 {x}^{2} - x - 15\right) \left(x + 5\right)$

Expand the rest of it gives you:
$y = 6 {x}^{3} + 29 {x}^{2} - 20 x - 75$

take the y to the other side to give the given answer.