# What is the standard form of y=(3x-5)(6x-2)?

Feb 4, 2016

$y = 18 {x}^{2} - 36 x + 10$

#### Explanation:

The standard form of an equation is:
$y = a {x}^{2} - b x + c$

So, you have to develop the right member which is the form :
$\left(a + b\right) \left(c + d\right)$
We develop as :
$\left(a \cdot c\right) + \left(a \cdot d\right) + \left(b \cdot c\right) + \left(b \cdot d\right)$

So :
$y = \left(3 x - 5\right) \left(6 x - 2\right)$
$y = \left(3 x \cdot 6 x\right) + \left(3 x \cdot - 2\right) + \left(- 5 \cdot 6 x\right) + \left(- 5 \cdot - 2\right)$
$y = 18 {x}^{2} - 6 x - 30 x + 10$
$y = 18 {x}^{2} - 36 x + 10$