What is the standard form of $y= (4x-4)(6x-2)(1/8x-1/4)$ ?

Question

1440 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-04-18T12:49:17

$3x^3-10x^2+9x-2$

When you multiply the first two parts of the equation you will get:

$y=(24x^2-8x-24x+8)((x/8)-(1/4))$

Now you can arrange it:

$y=(24x^2-32x+8)((x/8)-(1/4))$

Multiply terms again:

$y=3x^3-6x^2-4x^2+8x+x-2$

Arrange the above equation:

$y=3x^3-10x^2+9x-2$

This is the answer.

What is the standard form of y= (4x-4)(6x-2)(1/8x-1/4) y= (4x-4)(6x-2)(1/8x-1/4)?