# What is the standard form of  y= (4x-4)(6x-2)(1/8x-1/4)?

Apr 18, 2017

$3 {x}^{3} - 10 {x}^{2} + 9 x - 2$

#### Explanation:

When you multiply the first two parts of the equation you will get:

$y = \left(24 {x}^{2} - 8 x - 24 x + 8\right) \left(\left(\frac{x}{8}\right) - \left(\frac{1}{4}\right)\right)$

Now you can arrange it:

$y = \left(24 {x}^{2} - 32 x + 8\right) \left(\left(\frac{x}{8}\right) - \left(\frac{1}{4}\right)\right)$

Multiply terms again:

$y = 3 {x}^{3} - 6 {x}^{2} - 4 {x}^{2} + 8 x + x - 2$

Arrange the above equation:

$y = 3 {x}^{3} - 10 {x}^{2} + 9 x - 2$