What is the standard form of $y = - 9 (x - 1) (2 x - 4) (3 x - 1)$ $y= -9(x-1)(2x-4)(3x-1)$ ?

Question

1437 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-02-13T05:44:18

the standard form of expression is $y = a x^{3} + b x^{2} + c x + d$ $y=ax^3+bx^2+cx+d$

As the highest power in the algebraic expression

$- 9 (x - 1) (2 x - 4) (3 x - 1)$ $−9(x−1)(2x−4)(3x−1)$ is $x^{3}$ $x^3$ , the standard form of this is

$y = a x^{3} + b x^{2} + c x + d$ $y=ax^3+bx^2+cx+d$

Actual expansion of te expression gives us

$y = - 54 x^{3} + 180 x^{2} - 162 x + 36$ $y=-54x^3+180x^2-162x+36$

What is the standard form of y=−9(x−1)(2x−4)(3x−1) y= -9(x-1)(2x-4)(3x-1)?