What is the standard form of $y = (x + 2) (x - 6)$ $y= (x + 2)(x - 6)$ ?

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What is the standard form of $y = (x + 2) (x - 6)$ $y= (x + 2)(x - 6)$ ?

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Answer 1 · 2016-08-24T20:36:36

Standard form is $y = x^{2} - 4 x - 12$ $y=x^2-4x-12$

Explanation:

This is a function of degree $2$ $2$ i.e. quadratic equation and its standard firm is $y = a x^{2} + b x + c$ $y=ax^2+bx+c$ . Hence, the standard form for

$y = (x + 2) (x - 6)$ $y=(x+2)(x-6)$ is

= $x (x - 6) + 2 (x - 6)$ $x(x-6)+2(x-6)$

= $x^{2} - 6 x + 2 x - 12$ $x^2-6x+2x-12$

= $x^{2} - 4 x - 12$ $x^2-4x-12$

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What is the standard form of $y = (x + 2) (x - 6)$ $y= (x + 2)(x - 6)$ ?

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Explanation:

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What is the standard form of y=(x+2)(x−6)y= (x + 2)(x - 6) ?

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Explanation:

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What is the standard form of $y = (x + 2) (x - 6)$ $y= (x + 2)(x - 6)$ ?