What is the standard form of y= (x + 2)(x - 6) ?

Aug 24, 2016

Standard form is $y = {x}^{2} - 4 x - 12$

Explanation:

This is a function of degree $2$ i.e. quadratic equation and its standard firm is $y = a {x}^{2} + b x + c$. Hence, the standard form for

$y = \left(x + 2\right) \left(x - 6\right)$ is

= $x \left(x - 6\right) + 2 \left(x - 6\right)$

= ${x}^{2} - 6 x + 2 x - 12$

= ${x}^{2} - 4 x - 12$