# What is the standard form of y=(x^3 - 8)(x-2) ?

${x}^{4} - 2 {x}^{3} - 8 x + 16$
${x}^{3} \left(x - 2\right) - 8 \left(x - 2\right)$
$= {x}^{4} - 2 {x}^{3} - 8 x + 16$