Question

What is the standard form of `y= (x+3)(x+1)+(3x-7)^2`?

Answer 1

Standard form is `y=10x^2-38x+52`

Explanation:

As this a quadratic equation, standard form of this is

`y=ax^2+bx+c`

Hence simplifying `y=(x+3)(x+1)+(3x-7)^2`

= `(x^2+3x+x+3)+((3x)^2+2xx3xxx(-7)+7^2)`

= `(x^2+3x+x+3)+(9x^2-42x+49)`

= `10x^2-38x+52`