What is the standard form of  y= (x+3)(-x-1)+(3x-7)^2?

Feb 19, 2016

$8 {x}^{2} - 46 x + 46$

Explanation:

It is apparent that the highest degree of $x$ in the function

(x+3)(−x−1)+(3x−7)^2 is two. Expanding the function

(x+3)(−x−1)+(3x−7)(3x-7)

(x+3)(−x)−1(x+3)+3x(3x-7)-7(3x-7) or

$- {x}^{2} - 3 x - x - 3 + 9 {x}^{2} - 21 x - 21 x + 49$ or

$8 {x}^{2} - 46 x + 46$

As it is an function in degree $2$ of form $a {x}^{2} + b x + c$