# What is the standard form of y= x(3x-3)(x+2)?

Jan 7, 2016

The standard form is $y = 3 {x}^{3} + 3 {x}^{2} + 6 x$

#### Explanation:

We can multiply/expand the expression to get the standard form like this

$y = x \left(3 x - 3\right) \left(x + 2\right)$

Step 1: Multiply the last two factor, and combine like terms

$y = x \left(3 {x}^{2} + 6 x - 3 x - 6\right)$

$y = x \left(3 {x}^{3} + 3 x - 6\right)$

Step 2: Distribute the "x" to get

$y = 3 {x}^{3} + 3 {x}^{2} + 6 x$