What is the standard form of y= x(3x-3)(x+2)?

1 Answer
Jan 7, 2016

The standard form is y = 3x^3 +3x^2+6x

Explanation:

We can multiply/expand the expression to get the standard form like this

y = x( 3x-3)(x+2)

Step 1: Multiply the last two factor, and combine like terms

y = x(3x^2 +6x -3x -6)

y= x(3x^3 +3x-6)

Step 2: Distribute the "x" to get

y = 3x^3 +3x^2+6x