Question

What is the standard form of `y= ( x^4-1) (6-x)`?

Answer 1

In standard form `y=-x^5+6x^4+x-6`

Explanation:

`y=(x^4-1)(6-x)`

= `x^4(6-x)-1(6-x)`

= `6x^4-x^5-6+x`

and hence in standard form `y=-x^5+6x^4+x-6`