# What is the standard form of y= (-x-5)(8x-2) ?

Feb 19, 2016

$- 8 {x}^{2} - 38 x + 10$

#### Explanation:

Standard form for an expression is listing the terms , beginning with the term with the highest exponent of the variable followed by decreasing exponents until the last term , usually a constant.

begin by distributing the brackets.
Each term in the 2nd bracket must be multiplied by each term in the 1st.This can be done as follows.

thus : -x(8x - 2) - 5 (8x - 2 )

hence $- 8 {x}^{2} + 2 x - 40 x + 10 = - 8 {x}^{2} - 38 x + 10$

This expression is in standard form.