What is the standard form of #y= (-x-5)(8x-2) #?

1 Answer
Feb 19, 2016

#-8x^2 - 38x + 10#

Explanation:

Standard form for an expression is listing the terms , beginning with the term with the highest exponent of the variable followed by decreasing exponents until the last term , usually a constant.

begin by distributing the brackets.
Each term in the 2nd bracket must be multiplied by each term in the 1st.This can be done as follows.

thus : -x(8x - 2) - 5 (8x - 2 )

hence #-8x^2 + 2x - 40x + 10 = -8x^2 - 38x + 10#

This expression is in standard form.