What is the standard form of $y = (x - 6) (x - 4) (x - 1)$ $y= (x-6)(x-4)(x-1)$ ?

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What is the standard form of $y = (x - 6) (x - 4) (x - 1)$ $y= (x-6)(x-4)(x-1)$ ?

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Answer 1 · 2016-01-01T22:47:53

$y = x^{3} - 11 x^{2} + 34 x - 24$ $y=x^3-11x^2+34x-24$

Explanation:

To rewrite the equation in standard form, start by expanding the first two brackets:

$y = (x$ $y=(color(red)x$ $- 6) (x$ $color(green)(-6))(color(orange)x$ $- 4) (x - 1)$ $color(blue)(-4))(x-1)$

$y = (x (x)$ $y=(color(red)x(color(orange)x)$ $+ x (- 4)$ $color(red)(+x)(color(blue)(-4))$ $+ x (- 6)$ $color(orange)(+x)(color(green)(-6))$ $- 6 (- 4)) (x - 1)$ $color(green)(-6)(color(blue)(-4)))(x-1)$

Simplify.

$y = (x^{2} - 4 x - 6 x + 24) (x - 1)$ $y=(x^2-4x-6x+24)(x-1)$

$y = (x^{2} - 10 x + 24) (x - 1)$ $y=(x^2-10x+24)(x-1)$

Expand the remaining two brackets:

$y = (x^{2}$ $y=(color(red)(x^2)$ $- 10 x$ $color(orange)(-10x)$ $+ 24) (x$ $color(blue)(+24))(color(green)x$ $- 1)$ $color(purple)(-1))$

$y = x^{2} (x)$ $y=color(red)(x^2)(color(green)x)$ $+ x^{2} (- 1)$ $color(red)(+x^2)(color(purple)(-1))$ $- 10 x (x)$ $color(orange)(-10x)(color(green)x)$ $- 10 x (- 1)$ $color(orange)(-10x)(color(purple)(-1))$ $+ 24 (x)$ $color(blue)(+24)(color(green)x)$ $+ 24 (- 1)$ $color(blue)(+24)(color(purple)(-1))$

Simplify.

$y = x^{3} - x^{2} - 10 x^{2} + 10 x + 24 x - 24$ $y=x^3-x^2-10x^2+10x+24x-24$

$y = x^{3} - 11 x^{2} + 34 x - 24$ $y=x^3-11x^2+34x-24$

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What is the standard form of $y = (x - 6) (x - 4) (x - 1)$ $y= (x-6)(x-4)(x-1)$ ?

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Explanation:

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What is the standard form of y= (x-6)(x-4)(x-1)y=(x−6)(x−4)(x−1) y= (x-6)(x-4)(x-1)?

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What is the standard form of $y = (x - 6) (x - 4) (x - 1)$ $y= (x-6)(x-4)(x-1)$ ?