What is the standard form of $y = (x - x^{2}) (x - 8) - {(x + 3)}^{3}$ $y= (x-x^2)(x-8) -(x+3)^3$ ?

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Answer 1 · 2018-02-01T10:23:40

$y = - 2 x^{3} - 35 x - 27$ $y=-2x^3-35x-27$

$y = (x - x^{2}) (x - 8) - {(x + 3)}^{3}$ $y=(x-x^2)(x-8)-(x+3)^3$

$:.y=(x-x^2)(x-8)-(x+3)(x+3)(x+3)$

$:.y=-x^3+9x^2-8x-(x^3+9x^2+27x+27)$

$:.y=-x^3+9x^2-8x-x^3-9x^2-27x-27$

$:.y=-2x^3-35x-27$

What is the standard form of y= (x-x^2)(x-8) -(x+3)^3y=(x−x2)(x−8)−(x+3)3y= (x-x^2)(x-8) -(x+3)^3?