What is the sum of the coefficients when the following equation is balanced with the simplest whole numbers? If a substance has an understood 1 as the coefficient, do not forget to add it in. Fe2O3 (s) + C (s) → Fe (s) + CO2 (g)

1 Answer
Dec 21, 2017

Answer:

#12#

Explanation:

#Fe_2O_3 (s)+C (s)rarrFe (s)+CO_2 (g)#

Number of iron (Fe) atoms: 2 on the LHS, 1 on the RHS.
Number of carbon (C) atoms: 1 on the LHS, 1 on the RHS.
Number of oxygen (O) atoms: 3 on the LHS, 2 on the RHS.

Since we have an odd number of oxygens, we should probably balance that first.

Multiply by #2#: #2Fe_2O_3 (s)+C (s)rarrFe (s)+CO_2 (g)#

Let's balance the oxygen on the other side by multiplying by #3#: #2Fe_2O_3 (s)+C (s)rarrFe (s)+3CO_2 (g)#

Balance the carbon by multiplying by #3# on the LHS: #2Fe_2O_3 (s)+3C (s)rarrFe (s)+3CO_2 (g)#

Finally, balance the iron by multiplying by #4# on the LHS: #2Fe_2O_3 (s)+3C (s)rarr4Fe (s)+3CO_2 (g)#

This is our balanced equation in its simplest form.

The sum of the coefficients is #2+3+4+3=12#.