What is the sum of the measures of the interior angles of a pentagon?

Dec 19, 2015

Sum of the interior angles of a pentagon $= {540}^{\circ}$

Explanation:

The general formula for the sum of the interior angles of an n-gon (with $n \ge 3$) is
$\textcolor{w h i t e}{\text{XXX}} {180}^{\circ} \times \left(n - 2\right)$

A pentagon has $5$ sides (i.e. $n = 5$)

The diagram below may help to understand why this formula works: