What is the temperature of 0.59 mol of gas at a pressure of 1.5 atm and a volume of 12.9 L ?

1 Answer

Answer:

399.68 K or just over 126 celcius.

Explanation:

Assuming it behaves as an ideal gas, you can say #Pv=nRT# where P is pressure, v is volume, n is number of moles, R is the gas constant and T is temperature in Kelvins

Note that pressure and volume can be expressed in a number of different units, so you need to ensure that you use the gas constant in a form that is consistent with the other units that you're working with. As we're working in atmospheres as a pressure unit and litres as the unit of volume you need the gas constant in units of #L*atm*K^-1*mol^-1#, and in these units the value of the gas constant is #0.082057#

Now rearrange for T you have #T= (Pv)/(nR) = (1.5 * 12.9)/(0.59*0.082057) = 399.68 K#