# What is the temperature of 0.59 mol of gas at a pressure of 1.5 atm and a volume of 12.9 L ?

Jul 7, 2017

Assuming it behaves as an ideal gas, you can say $P v = n R T$ where P is pressure, v is volume, n is number of moles, R is the gas constant and T is temperature in Kelvins
Note that pressure and volume can be expressed in a number of different units, so you need to ensure that you use the gas constant in a form that is consistent with the other units that you're working with. As we're working in atmospheres as a pressure unit and litres as the unit of volume you need the gas constant in units of $L \cdot a t m \cdot {K}^{-} 1 \cdot m o {l}^{-} 1$, and in these units the value of the gas constant is $0.082057$
Now rearrange for T you have $T = \frac{P v}{n R} = \frac{1.5 \cdot 12.9}{0.59 \cdot 0.082057} = 399.68 K$