# What is the temperature of 2.0 moles of a gas occupying a volume of 5.0 L at 2.46 atm?

##### 1 Answer

#### Answer:

#### Explanation:

This is a fairly straightforward application of the ideal gas law equation, which looks like this

#color(blue)(PV = nRT)" "# , where

*universal gas constant*, usually given as

*Kelvin*

Rearrange this equation to solve for

#PV = nRT implies T = (PV)/(nR)#

Before plugging in your values, check to make sure that the units given to you **match** the units used in the expression of the *universal gas constant*.

As it stands, *moles*, *atm*, and *liters* are all units used for

Plug in your values to get

#T = (2.46 color(red)(cancel(color(black)("atm"))) * 5.0 color(red)(cancel(color(black)("L"))))/(2.0 color(red)(cancel(color(black)("moles"))) * 0.0821 (color(red)(cancel(color(black)("atm"))) * color(red)(cancel(color(black)("L"))))/(color(red)(cancel(color(black)("mol"))) * "K")) = "74.91 K"#

Rounded to two sig figs, the answer will be

#T = color(green)("75 K")#