What is the temperature of 2.0 moles of a gas occupying a volume of 5.0 L at 2.46 atm?
1 Answer
Explanation:
This is a fairly straightforward application of the ideal gas law equation, which looks like this
#color(blue)(PV = nRT)" "# , where
Rearrange this equation to solve for
#PV = nRT implies T = (PV)/(nR)#
Before plugging in your values, check to make sure that the units given to you match the units used in the expression of the universal gas constant.
As it stands, moles, atm, and liters are all units used for
Plug in your values to get
#T = (2.46 color(red)(cancel(color(black)("atm"))) * 5.0 color(red)(cancel(color(black)("L"))))/(2.0 color(red)(cancel(color(black)("moles"))) * 0.0821 (color(red)(cancel(color(black)("atm"))) * color(red)(cancel(color(black)("L"))))/(color(red)(cancel(color(black)("mol"))) * "K")) = "74.91 K"#
Rounded to two sig figs, the answer will be
#T = color(green)("75 K")#