What is the total number of oxygen atoms on the left-hand side of #2Ca_2(PO_4)_2(s) + 4SiO_2(s) + 12C(s) -> 4CaSiO_3(s) + P_4(s) + 12CO(g)#?
24 atoms of Oxygen.
On the LHS of the equation we have 2 formula units of
Each Formula unit has two P
On the LHS of the equation we have 4 molecules of Si
and each molecule has two Oxygen atoms, so four will have 4 x2 = 8 Oxygen atoms.
In all 16 + 8 = 24 Oxygen atoms are on the LHS of the equation