Question

What is the value of `(3m^2 - mn)/(2mn^2)` when `m = -1 and n=2`?

Answer 1

`-0.0625`

Explanation:

`(3m^2-mn)/(2mn^2), m=-1, n=2=`

`(3(-1)^2-(-1)(2))/(2(-1)(2)^2)=(3--2)/(2(-4))=5/-8=-0.0625`