What is the value of the discriminant for the quadratic equation #7r^2 -14r + 10 = 0#?

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Answer 1 · 2018-06-07T18:55:50

#-84#

For any quadratic of the form

#ar^2+br+c#,

the discriminant is equal to

#b^2-4ac#

In our quadratic, we know that #a=7, b=-14# and #c=10#, so let's just plug these values into the value for the discriminant. We get

#(-14)^2-4(7)(10)#

which simplifies to

#196-4(70)#

#=>196-280=color(blue)(-84)#

Therefore, the value of our discriminant is equal to

#color(blue)(-84)#

Hope this helps!