Question

What is the vapor pressure of water at 105°C?

Answer 1

You can do this with the Antoine equation:

`log P = A - B/(C+T)`

where:

• `P` is the vapor pressure of water.
• `T` is the water temperature in celsius.
• `A,B,` and `C` are the Antoine constants for water.

When the water temperature is in the range of `1 - 100^@ "C"`:

`A=8.07131, B=1730.63, C= 233.426`

When the water temperature is in the range of `99-374^@ "C"`:

`A=8.14019, B=1810.94, C=244.485`

If you calculate using this way you will get answer in `"torr"`:

`P = 10^(A - B/(C+T))`

`= 10^{8.14019-{1810.94}/{105+244.485}}`

`= 10^{8.14019-5.18174}`

`= 10^{2.95845}`

`=` `"908.76 torr"`

This is the water pressure at `105^@ "C"`.