# What is the vapor pressure of water at 105°C?

##### 1 Answer

Feb 8, 2017

You can do this with the Antoine equation:

#log P = A - B/(C+T)# where:

#P# is the vapor pressure of water.#T# is the water temperature in celsius.#A,B,# and#C# are the Antoine constants for water.

When the water temperature is in the range of

#A=8.07131, B=1730.63, C= 233.426#

When the water temperature is in the range of

#A=8.14019, B=1810.94, C=244.485#

If you calculate using this way you will get answer in

#P = 10^(A - B/(C+T))#

#= 10^{8.14019-{1810.94}/{105+244.485}}#

#= 10^{8.14019-5.18174}#

#= 10^{2.95845}#

#=# #"908.76 torr"#

This is the water pressure at