# What is the vertex of #7y= 12(x-15)^2 +12#?

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#"divide both sides by 7"#

#rArry=12/7(x-15)^2+12/7#

#"the equation of a parabola in "color(blue)"vertex form"# is.

#color(red)(bar(ul(|color(white)(2/2)color(black)(y=a(x-h)^2+k)color(white)(2/2)|)))#

#"where "(h,k)" are the coordinates of the vertex and a"#

#"is a multiplier"#

#y=12/7(x-15)^2+12/7" is in vertex form"#

#rArrcolor(magenta)"vertex "=(15,12/7)#

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#### Answer:

The vertex happens to be

#### Explanation:

The given equation is:

The curve is symmetrical about the x axis

Differentiating the equation wrt x

The vertex coresponds to the point where the slope is zero.

Equating

ie

Substituting for x in the equation of the curve

Thus, the vertex happens to be

Describe your changes (optional) 200