# What is the vertex of y = 2(x - 3)^2 + 1?

Mar 8, 2017

$\left(3 , 1\right)$

#### Explanation:

The answer happens to be in the equation without any work needed!

This equation is already in vertex form. The equation for vertex form is $y = a {\left(x - h\right)}^{2} + k$

In this equation, $\left(h , k\right)$ is the vertex. When you look at your equation: $y = 2 {\left(x - 3\right)}^{2} + 1$, the $h , k$ is $\left(3 , 1\right)$.

*Note: in vertex form, there is a negative sign in front of the $h$, so you must take whatever h value there is an make is opposite. Thus, your vertex is $\left(3 , 1\right)$ and not $\left(- 3 , 1\right)$.