What is the vertex of #y=2x^2+6x+4#?
Method 1: Calculus approach
Vertex is where the gradient of the curve is 0.
Equate that to 0 such that:
Method 2: Algebraic approach.
Complete the square to find the turning points, also known as the vertex.
Notice here that you have to multiply BOTH terms by 2, as 2 was the common factor which you took out of the entire expression!
Therefore, the turning points can be picked up such that