Question

What is the volume of 2.10 moles of chlorine gas (`Cl_2`) at 273 K and 1.00 atm?

Answer 1

`47.0L`

Explanation:

`PV=nRT`, where `R=0.082057" L atm "mol^-1 K^-1`
`:. V=(nRT)/P`
`V=(2.10molxxRxx273K)/(1.00atm)=47.0L`