# What is the volume of a tin block that has a mass of 95.04 grams at STP?

"Density " (rho)=("Mass")/("Volume")
We need the density of tin, ${\rho}_{S n}$ $=$ $7.37$ $g \cdot c {m}^{-} 3$.
So we divide $\text{mass}$ by $\text{density}$ to get volume in $c {m}^{3}$;
i.e. $\frac{95.04 \cdot \cancel{g}}{7.37 \cdot \cancel{g} \cdot c {m}^{-} 3}$ $\cong$ $14 \cdot c {m}^{3}$