# What is the VSEPR shape for CH_3OH?

Around each $C$ and $O$ there are $4$ electron pairs, bonding and non-bonding. To a first approximation VSEPR specifies tetrahedral geometries about $C$ and $O$, and indeed there are.
The $\angle H - C - H$ and $\angle H - C - O$ bonds have a bond angle of approx. ${109.5}^{\circ}$. The $H - O - C$ bond angle tends to be compressed slightly due to the oxygen lone pairs which are stereochemically active, so maybe the $H - O - C$ bond angle $=$ approx. $104 - {5}^{\circ}$. Capisce?