# What is the work done in using a cable that weighs 2 pound per foot to lift a weight of 800 pounds a distance of 500 feet?

Dec 8, 2014

Work done = $9 \times {10}^{5} f t . l b$

The total weight of cable = $2 \times 500 = 1000 l b$

So total load = 1000 + 800 = 1800lb.

Work done = force x distance = 500 x 1800 = 900000 = $9 \times {10}^{5} f t l b$