What is the x intercept and y intercept of #y= 4(x+2)#?
1 Answer
The intercept with one axis is simply when the other variable goes to zero. So...

The
#x# intercept is found by letting#y = 0# . 
The
#y# intercept is found by letting#x = 0# .
The result is shown in this graph:
graph{4(x+2) [11.04, 11.46, 10.585, 0.665]}
#(x,y) = overbrace((2","0))^"xintercept", overbrace((0","8))^"yintercept"#
Here is how I would do it.
Let
#0 = 4(x + 2)#
#0 = 4x  8#
#4x = 8#
#x = 8/4 = 2#
As a result, the
One way to do this is to notice that in solving for the
#y = 4x  8#
The
Another way to do it is by letting
#y = 4(0 + 2)#
#= 8#
As a result, the