What is the x- intercept and y- intercept of #-y= -(4x+2)-4#?
# = -3/2 #
y-intercept = 6
I'm going to start by rewriting the equation.
ie - y = - 4x -2 -4 = - 4x - 6
( multiply through by -1) gives : y = 4x + 6
when a straight line crosses the x -axis the y-coord is zero. By letting y = 0 and substituting into the equation will give corresponding x-coord.
let y = 0 : 4x + 6 = 0
#rArr 4x = -6 rArr x = -6/4 = -3/2 #
Similarly when the line crosses the y-axis the x-coord will be zero.
let x = 0 : y = 0 + 6 = 6