What is the $y$ $y$ -intercept of $2 x - y + 5 = 0$ $2x - y + 5 = 0$ ?

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Answer 1 · 2018-06-20T06:36:03

The $y$ $y$ -intercept is at $(0, 5)$ $(0, 5)$ .

To find the $y$ $y$ -intercept, we just plug in $0$ $0$ for the $x$ $x$ -value in the equation and find $y$ $y$ :
$2 x - y + 5 = 0$ $2x - y + 5 = 0$

Plug in $0$ $0$ for $x$ $x$ :
$2 (0) - y + 5 = 0$ $2(0) - y + 5 = 0$

Simplify:
$0 - y + 5 = 0$ $0 - y + 5 = 0$

$5 - y = 0$ $5 - y = 0$

Subtract $5$ $color(blue)5$ from both sides:
$5 - y - 5 = 0 - 5$ $5 - y quadcolor(blue)(-quad5) = 0 quadcolor(blue)(-quad5)$

$- y = - 5$ $-y = -5$

Divide both sides by $- 1$ $color(blue)(-1)$ :
$\frac{- y}{- 1} = \frac{- 5}{- 1}$ $(-y)/color(blue)(-1) = (-5)/color(blue)(-1)$

Therefore,
$y = 5$ $y = 5$

So the $y$ $y$ -intercept is at $(0, 5)$ $(0, 5)$ .

To show that this point is indeed the $y$ $y$ -intercept, here's a graph of this equation (desmos.com):
enter image source here

For more information on finding intercepts, feel free to watch this Khan Academy video:

Hope this helps!

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