What is the y intercept of #y=3(x-11)^2#?

1 Answer
May 30, 2018

Answer:

#(0,363)#

Explanation:

The #y# intercept is, by definition, the point in which the function crosses the #y# axis. All the points on the #y# axis can be written as #P = (0,y)#.

So, the #y# intercept of any function #f(x)# is simply the point #(0,f(0))#, assuming of course that #f# is defined at #x=0#.

In your case,

#f(x) = 3(x-11)^2 \implies f(0) = 3(0-11)^2 = 3\cdot 121 = 363#