# What is #x# and #y# in this system of equations: #y+x =6# and #3y -x = 3#?

##### 1 Answer

Apr 23, 2017

#### Explanation:

Solve using the method of addition/ elimination

#y+x=6#

#3y-x=3#

Add the first equation to the second

#4y=9#

#y=9/4#

Substitute the value of

#y+x=6#

#9/4+x=6#

#x=15/4#

Writing that as a point would be

#rArr(15/4,9/4)#