# What is x if #ln(3x^2) + ln(x^4) + ln(7) =0#?

##### 2 Answers

Use the logarithm laws.

#ln(3x^2 * x^4 * 7) = 0#

#21x^6 = e^0#

#x^6 = 1/21#

#x = +-root(6)(1/21)#

Hopefully this helps!

The solutions are

(or

#### Explanation:

Use this logarithm rule:

Here's this rule applied to our equation:

Convert to exponential form:

Since the root is an even power, we add a plus-or-minus sign:

You can check using a graphing calculator:

Since the values of the zeroes are the same as our answer, we are correct. Hope this helped!