# What is Y = x^2 - 6x - 15 in vertex form?

Apr 10, 2018

The general vertex form is y=a(x−h)^2+k where $\left(h , k\right)$ is the vertex.

#### Explanation:

$y = {x}^{2} - 6 x - 15$

$y = {x}^{2} - 6 x + 9 - 9 - 15$

y=(x^2−6x+9)−24

Vertex form:
f(x)=(x−3)^2−24

Vertex:
(3,−24)