What mass in grams of sodium hydroxide is produced if 20.0 g of sodium metal reacts with excess water according to the chemical equation #2Na(s) 2H_2O(l)->2NaOH(aq)+H_2(g)#?

1 Answer
Feb 23, 2016

Answer:

#Na(s) + H_2O(l) rarr NaOH(aq) + 1/2H_2(g)#

Moles of NaOH #=# #(20.0*g)/(22.99*g*mol^-1)# #=# #??# #mol#

Explanation:

Clearly, there is a 1:1 equivalence between the moles of sodium, and moles of sodium hydroxide. One half an equiv of dihydrogen gas is also produced. We know that #1# #mol# of gas occupies #24.5# #L# at #298# #K#, and #1# #atm#. What volume of dihydrogen would be evolved under the above conditions?