# What mass of iron has a volume of 6.3 cm^3?

Mar 18, 2018

$\approx 49.52 \setminus \text{g}$

#### Explanation:

Iron has a density of $7.86 \setminus {\text{g/cm}}^{3}$.

The density formula is:

$\rho = \frac{m}{V} ,$

where $\rho$ is density, $m$ is mass, and $V$ is volume.

To find the mass given the density, we use the equation:

$m = \rho \cdot V$

So, plugging in the given values, we get

$m = \left(7.86 \setminus {\text{g")/(color(red)cancelcolor(black)("cm"^3))*6.3color(red)cancelcolor(black)("cm}}^{3}\right)$

$\approx 49.52 \setminus \text{g}$