What mass of water will change its temperature by 3 C when 525 J of heat is added to it? The specific heat of water is 4-.8 J/gC

1 Answer
Dec 18, 2016

Answer:

#m= 36.5g#

Explanation:

To obtain the mass of water, let's use the equation below:
http://slideplayer.com/slide/4758097/

Based on the information you've provided, we know the following variables:

#DeltaT# = #3^oC#
#Q# = 525 J
#C# = #4.8J/(gxx^oC)#

All we have to do is rearrange the equation to solve for m. This can be accomplished by dividing both sides by #C# and #Delta T# to get m by itself like this:

#m = Q/(DeltaTxxC)#

Now, we just plug in the known values:

#m = (525cancelJ)/(3^cancel"oC"xx4.8cancelJ/(gxx^(cancel"oC")))#

#m = 36.5 g #