# What mass of water will change its temperature by 3 C when 525 J of heat is added to it? The specific heat of water is 4-.8 J/gC

Dec 18, 2016

$m = 36.5 g$

#### Explanation:

To obtain the mass of water, let's use the equation below:

Based on the information you've provided, we know the following variables:

$\Delta T$ = ${3}^{o} C$
$Q$ = 525 J
$C$ = $4.8 \frac{J}{g {\times}^{o} C}$

All we have to do is rearrange the equation to solve for m. This can be accomplished by dividing both sides by $C$ and $\Delta T$ to get m by itself like this:

$m = \frac{Q}{\Delta T \times C}$

Now, we just plug in the known values:

m = (525cancelJ)/(3^cancel"oC"xx4.8cancelJ/(gxx^(cancel"oC")))

$m = 36.5 g$