Question

What mass of water will change its temperature by 3 C when 525 J of heat is added to it? The specific heat of water is 4-.8 J/gC

Answer 1

`m= 36.5g`

Explanation:

To obtain the mass of water, let's use the equation below:

Based on the information you've provided, we know the following variables:

`DeltaT` = `3^oC`
`Q` = 525 J
`C` = `4.8J/(gxx^oC)`

All we have to do is rearrange the equation to solve for m. This can be accomplished by dividing both sides by `C` and `Delta T` to get m by itself like this:

`m = Q/(DeltaTxxC)`

Now, we just plug in the known values:

`m = (525cancelJ)/(3^cancel"oC"xx4.8cancelJ/(gxx^(cancel"oC")))`

`m = 36.5 g`