# What pressure is exerted by 0.450 mol of a gas at 25 degrees Celsius if the gas is in a 0.50 L container?

Mar 1, 2016

$P = 22 a t m$
$P V = n R T$.
Therefore, $P = \frac{n R T}{V} = \frac{0.450 \cancel{m o l} \times 0.0821 \frac{\cancel{L} \cdot a t m}{\cancel{m o l} \cdot \cancel{K}} \times 298 \cancel{K}}{0.50 \cancel{L}} = 22 a t m$