# What's the electron configuration for Oganesson? Atomic number-118

Jan 15, 2018

$\left[R n\right] 7 {s}^{2} 5 {f}^{14} 6 {d}^{10} 7 {p}^{6}$

#### Explanation:

For oganesson, we should probably use noble gas notation (to indicate that it has the same electron configuration as that noble gas to a certain point) because it would get too long otherwise.

The closest noble gas to oganesson is radon. So, make that the first part of the answer:
$\left[R n\right]$

Then, read the periodic table from left to right, beginning from radon.

As you see, to get to oganesson, we go through:

1. The complete $7 s$ orbital. The maximum number of electrons in the $s$ orbital is $2$. It's full, so oganesson has $2$ electrons in the $7 s$ orbital.
2. The complete $5 f$ orbital (for the $f$ orbitals, subtract $2$ from the period number to get the energy level. So, for us, it would be $7 - 2 = 5$.) The maximum number of electrons in the $f$ orbital series is $14$. It's full, so oganesson has $14$ electrons in the $5 f$ orbital.
3. The complete $6 d$ orbital. The maximum number of electrons in the $d$ orbital series is $10$. It's full, so oganesson has $10$ electrons in the $6 d$ orbital.
4. The complete $7 p$ orbital. The maximum number of electrons in the $p$ orbital series is $6$. It's full, so oganesson has $6$ electrons in the $7 p$ orbital.

Put that information all together:

$\left[R n\right] 7 {s}^{2} 5 {f}^{14} 6 {d}^{10} 7 {p}^{6}$