# What SI units are used to measure volume?

Mar 16, 2018

I think ${m}^{3}$

#### Explanation:

In the gas law stuff, there is a gas constant, R, in which R=8.134 J/molK

A Joule has units of $\frac{k g \times {m}^{2}}{{s}^{2}}$

R = $\text{PV"/"nT}$, and the moles and temp cancel from the gas constant, so that means
$\frac{k g \times {m}^{2}}{{s}^{2}}$ = PV

Pressure is in Newtons, $\frac{\text{F}}{m} ^ 2$, or $\text{kg*m"/(m^2s^2)}$

$\frac{k g \times {m}^{2}}{{s}^{2}}$ = $\frac{\text{kg*m}}{{m}^{2} {s}^{2}}$V

If you solve for V, you get ${m}^{3}$
That was the round-about way of doing it, but I know energy is Joules and Pressure is Newtons...so obviously should use the ideal gas law :)